8x+26=x^2+5x+4

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Solution for 8x+26=x^2+5x+4 equation:



8x+26=x^2+5x+4
We move all terms to the left:
8x+26-(x^2+5x+4)=0
We get rid of parentheses
-x^2+8x-5x-4+26=0
We add all the numbers together, and all the variables
-1x^2+3x+22=0
a = -1; b = 3; c = +22;
Δ = b2-4ac
Δ = 32-4·(-1)·22
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{97}}{2*-1}=\frac{-3-\sqrt{97}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{97}}{2*-1}=\frac{-3+\sqrt{97}}{-2} $

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